(4-x)(12-7x+x^2)=0

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Solution for (4-x)(12-7x+x^2)=0 equation:


Simplifying
(4 + -1x)(12 + -7x + x2) = 0

Multiply (4 + -1x) * (12 + -7x + x2)
(4(12 + -7x + x2) + -1x * (12 + -7x + x2)) = 0
((12 * 4 + -7x * 4 + x2 * 4) + -1x * (12 + -7x + x2)) = 0
((48 + -28x + 4x2) + -1x * (12 + -7x + x2)) = 0
(48 + -28x + 4x2 + (12 * -1x + -7x * -1x + x2 * -1x)) = 0
(48 + -28x + 4x2 + (-12x + 7x2 + -1x3)) = 0

Reorder the terms:
(48 + -28x + -12x + 4x2 + 7x2 + -1x3) = 0

Combine like terms: -28x + -12x = -40x
(48 + -40x + 4x2 + 7x2 + -1x3) = 0

Combine like terms: 4x2 + 7x2 = 11x2
(48 + -40x + 11x2 + -1x3) = 0

Solving
48 + -40x + 11x2 + -1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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